-4.9x^2+265x+150=0

Solution for -4.9x^2+265x+150=0 equation:

-4.9x^2+265x+150=0

a = -4.9; b = 265; c = +150;
Δ = b2-4ac
Δ = 2652-4·(-4.9)·150
Δ = 73165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(265)-\sqrt{73165}}{2*-4.9}=\frac{-265-\sqrt{73165}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(265)+\sqrt{73165}}{2*-4.9}=\frac{-265+\sqrt{73165}}{-9.8}
$